WebOct 14, 2015 · select substr (zip, 1, 4) as region, sum (minutes) as minutes, rank () over (order by sum (minutes) desc) as therank from tableT where s.no > 1 group by substr (zip, 1, 4) order by minutes desc; Share Improve this answer Follow answered Oct 13, 2015 at 22:07 Gordon Linoff 1.2m 56 633 771 1 thank you Gordon Linoff . Webhex_decode_string 功能 将输入字符串中每一对十六进制数字解析为一个数字,并将解析得到的数字转换为表示该数字的字节,然后返回一个二进制字符串。 该函数是 hex () 函数的反向函数。 语法 VARCHAR hex_decode_string(VARCHAR str); 参数说明 str :要解码的字符串,必须为 VARCHAR 类型。 如果发生以下任何情况,则返回一个空字符串: 输入字符串 …
Python Check if substring is part of List of Strings
WebAug 15, 2024 · If your SQL dialect supports CHARINDEX, it's a lot easier to use it instead: SELECT * FROM MyTable WHERE CHARINDEX ('word1', Column1) > 0 AND CHARINDEX ('word2', Column1) > 0 AND CHARINDEX ('word3', Column1) > 0 Also, please keep in mind that this and the method in the accepted answer only cover substring matching rather … WebApr 15, 2024 · 1 Answer Sorted by: 3 You may use the pattern [^0-9,]: IF (@inputvariable LIKE '% [^0-9,]%') BEGIN RAISERROR ('@inputvariable can only contain numbers and commas', 18, 1) RETURN END The above would raise an error whenever the input variable contains a character which is not a digit or comma. Share Improve this answer Follow answered 10 … raised flower bed plant ideas
SQL query for delimited string - Stack Overflow
WebJun 30, 2024 · Method 1 - Using CHARINDEX () function CHARINDEX () This function is used to search for a specific word or a substring in an overall string and returns its starting … WebApr 14, 2024 · The substring function with three parameters, substring (string from pattern for escape-character), provides extraction of a substring that matches an SQL regular expression pattern. As with SIMILAR TO, the specified pattern must match the entire data string, or else the function fails and returns null. WebDec 6, 2024 · You just flip the two terms in your LIKE operator: SELECT * FROM mytable WHERE 'words' LIKE CONCAT ('%',name,'%') I believe that LOCATE () and INSTR () may work here too which looks nicer since there isn't a need for concatenating the search term/substring. SELECT * FROM mytable WHERE INSTR ('words', name) > 0 Share Improve … raised flower bed sink