WebWhen $$n=4,{s}_{4}=\dfrac{4}{2}\left[2\times 24+\left(4-1\right)\left(-3\right)\right]=2\left[48-9\right]=2\times 39=78$$
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Web28 mrt. 2024 · Ex 5.3, 18 Important . Ex 5.3, 19 ... Ex 5.3, 4 - Chapter 5 Class 10 Arithmetic Progressions (Term 2) Last updated at March 28, 2024 by Teachoo. This video is only available for Teachoo black users Subscribe Now Get live Maths 1-on-1 Classs - Class 6 to 12. Book 30 minute class for ₹ 499 ₹ 299. Web16 dec. 2024 · About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators ...
WebHow many terms of the a.p: 24,21,18,.must be taken so that the sum is 78? View answer. How many terms of the AP: 9,17,25 .must be taken to give a sum of 636? ... How many terms of an ap 45,39,33,.must be taken so thier sum is 180? for Class 10 2024 is part of Class 10 preparation. WebHow many terms of the A.P: 24,21,18,.... must be taken so that their sum is 78? Medium Solution Verified by Toppr ⇒S n= 2n[2a+(n−1)d] ⇒78= 2n(2a+(n−1)d) ⇒78= 2n(2(24)+(n+1)(−3)) ⇒156=n(48−3n+3) ⇒156=n(51−3n) ⇒156=51n−3n 2 ⇒3n 2−51n+156=0 ⇒3n 2−12n−39n+156=0 ⇒3n(n−4)−3q(n−4)=0 ⇒n=4 or n= 339=13 Solve …
WebHow many terms of the A.P. 24, 21, 18, … must be taken so that the sum is 78? Explain the double answer. WebLet the number of terms taken be n. THe given A.P is 24, 21, 18, ..... Here a = 24 and d = 21 - 24= -3 `S = n/2[2a + (n - 1)d]` `=> 78 = n/2 [2 xx 24 + (n - 1)xx (-3)]`
Web3 apr. 2024 · First term (t 1) = a = 3, Common difference (d) = 8 – 3 = 5 and last term (t n) = 78 The general term of A.P is t n = a + (n - 1) d 78 = 3 + (n – 1)5 ⇒ 78 = 3 + 5n – 5 ⇒ 78 = - 2 + 5n ⇒ 78 + 2 = 5n ⇒ 80 = 5n ⇒ n = 16 ∴ 78 is 16th term of A.P: 3, 8,13, 18,... Download Solution PDF Share on Whatsapp Latest SSC CGL Updates Last updated on Apr 3, 2024
Web29 mrt. 2024 · Here, a = 24 d = 21 – 24 = –3 Also, given Sum = 78 Sn = 78 We have to find value of n Putting these values in equation Sum = 𝒏/𝟐 [𝟐𝒂+ (𝒏−𝟏)𝒅] 78 = 𝑛/2 [2×24+ (𝑛−1) (−3)] 78 … how much is employer prsi in irelandWeb10 jul. 2024 · How many terms of the AP : 24, 21,18,... must be taken so that their sum is 78? class-10 arithmetic-progressions Answer 0 votes Best answer a=24 and d=21-24=-3 S n = n 2 (2a + (n − 1)d) S n = n 2 ( 2 a + ( n - 1) d) 78 = n 2 (2(24) + (n − 1)( − 3)) 78 = n 2 ( 2 ( 24) + ( n - 1) ( - 3)) 156=n (48-3n+3) n2 − 51n + 156 = 0 n 2 - 51 n + 156 = 0 how do chickens fartWebThe 8th term of an AP is 18 more than the second term of the AP. The third term is 7. Formula: n-th term of an AP = a + (n - 1)d, where a is the first term, n is the total number … how do chickens drink waterWeb29 jan. 2024 · Best answer Here, a = 24, d = 21 – 24 = –3, Sn = 78. We need to find n. Both values of n are admissible. So, the number of terms is either 4 or 13. ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series Class 12 Chapterwise MCQ Test Class 11 Chapterwise Practice Test Class 10 Chapterwise … how much is employee pension contributionWeb14 mei 2024 · How many terms of the AP : 24, 21, 18, . . . must be taken so that their sum is 78? Q.38. How many terms of the AP : 9, 17, 25, . . . must be taken to give a sum of … how much is employer contribution to cpfWeb19 apr. 2024 · So, the sum of the first 20 terms of the AP is 250. Example:How many terms of the AP: 24, 21, 18 … must be taken so that their sum is 78? Solution:Here, a = 24, d = 21 – 24 = –3, Sn= 78. We need to find n. We know that Sn= n/2[2a + (n – 1) d] Therefore, 78 = n/2[2 × 24 + (n – 1) × (-3)] 78 × 2 = n [48 – 3n + 3] 156 = 51n – 3n2 3n2– … how much is employer taxesWebLet's check sum of 4 terms ⇒ a 4 = a 3 + d ⇒ a 4 = 18 + (-3) = 15 ∴ S 4 = 24 + 21 + 18 + 15 = 78. By formula, a n = a + (n - 1)d ⇒ a 5 = 24 + (5 - 1) (-3) ⇒ a 5 = 24 + 4 (-3) ⇒ a 5 = … how much is employers national insurance uk